证明:根号2是无理数(from ‘plus magazine’)

The square root of 2 is irrational

The first thing you might ask if you saw this definition is – are there any irrational numbers? How do we know that Ö2, say, is irrational?

To prove that Ö2 is irrational, suppose the contrary, namely that it is rational, so that there are integers p and q such that
(p/q)2 = 2.
We can also assume that p and q are mutually prime, that is, that they have no common divisors. Then p2 = 2q2 so that p2 is divisible by 2. This means there is another integer s such that
p2 = 2s.
Now suppose p is odd. Then p=2r+1 for some integer r. Substituting into the formula for p2 and multiplying out we see that
p2 = (2r+1)2;

4r2 + 4r +1 = 2s.
But this isn’t possible, because the right hand side is odd, but the left hand side is even.
This contradiction means that p is even, so it can be written as p=2r for some integer r. Substituting into the formula
(p/q)2 = 2,
we get that
(2r/q)2 = 2.
Dividing across by 2, this means that
2r2 = q2,
so q2 is even, and q is even (just as we could prove p was). But this is a contradiction, because we assumed p and q had no common factors. This contradiction means that Ö2 is not rational.
 
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Have fun, my friends!

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